Ajet is traveling at 580 miles per hour at a bearing of 50 degree north. after flying for 1.7 hours in the same direction, how far east will the plane have traveled?

The jet flies 755.32 miles east after flying for 1.7hrs at a bearing of 50 degree North.

Step-by-step explanation:

The distance covered by the jet can be deducted from velocity = distance / time

therefore distance = velocity x time

distance = 580miles/hr x 1.7hrs

= 986 miles

At bearing of 50°, distance towards the east can be generated using the right angle triangle model such that the distance covered x miles can be generated using Sin(theta)  = opp/hyp as shown in the attached diagram

theta is the angle covered = 50°

opposite is the distance covered by the jet towards the east (x)

hypotenuse is the distance covered after flying for 1.7hrs

therefore Sin(50) = x / 986

x = 986 Sin 50

x = 986 × 0.7660

x = 755.32 miles

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer