Find the position function of a particle moving along a coordinate line that satisfies the given condition v(t) = 6t2 - 4t + 5,s(1) = - 4 s(t) =

Step-by-step explanation:

The position is the integrative of the velocity.

We have that:

So

In which k is the constant of integration, which we use the initial condition to find.

s(1) = -4. So

So

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

mk./km: lm

step-by-step explanation:

,mlmlm

; mk

lk