Two solutions of salt water contain 0.07% and 0.23% salt respectively. a lab technician wants to make 1 liter of solution which contains 0.11% salt. how much of each solution should she use?

0.75 liter of 0.07 % is used and 0.25 liter of 0.23 % salt is used

Solution:

We have to 1 liter of final solution

Let "x" be the salt solution of 0.07 %

Then, (1 - x) is the salt solution of 0.23 %

Then final solution should be 1 liter of solution which contains 0.11 % salt

Thus, 0.07 % of "x" is mixed with 0.23 % of (1 - x) to make a solution 0.11 % of 1 liter

Thus a equation is framed as:

0.07 % of x + 0.23 % of (1 - x) = 0.11 % of 1

Thus 0.75 liter of 0.07 % is used

And,

1 - x = 1 - 0.75 = 0.25

Thus 0.25 liter of 0.23 % salt is used

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

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