Which are the solutions of x2 = –13x – 4?

You first have to rearrange the equation to give x2 + 13x + 4 = 0. In this equation, a =1, b=13, and c=4. Since you can not get the roots by easily factoring the equation, you have to use the quadratic equation. The quadratic equation is x = (-b +/- sqrt (b^2-4ac))/2a. If our equation, plugging in the numbers into the equation gives the following expressions: x= (-13 + sqrt (13^2 - (4)(1)(4)))/(2 x 1) , (-13 - sqrt (13^2 - (4)(1)(4)))/(2x1). The final answers will be x = (-13/2) +( 3/2)sqrt (17) , (13/2) - (3/2)sqrt(17)

The mode of the numbers is 29.

2/1 or just 2. sorry if i get this wrong