Aweather balloon is launched from the ground at a spot 250 yards from a 65 foot royal palm tree . what is the minimal angle of elevation at which the balloon must take off in order to avoid hitting the tree? assume that the balloon flies in a straight line and the angle of elevation stays constant.

Angle of elevation at which the balloon must take off in order to avoid hitting the tree is 5 degrees

Step-by-step explanation:

Given:

The height of the tree  = 65 foot

The distance between the tree and the spot from which the balloon is launched = 250 yards

To find:

The angle of elevation at which the balloon must take off in order to avoid hitting the tree = ?

Solution:

Converting the yards to feet

1 yards = 3 feet

250 yards = 3 x 250 = 750 yards

Refer the below figure, The angle x is the angle of elevation at which the the ball must be thrown so that it does not Hit the tree

Substituting the values

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

d) 48

step-by-step explanation:

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