1. a student bought two juice pouches for $1.25 each and 3 bags of chips. write and solve an equation to determine the cost of chips, c.

variable:
equation:

solution:

A student bought two juice pouches for $1.25 each and 3 bags of chips. The total cost was $5.05 .write and solve an equation to determine the cost of a bag of chips,c

variable : c (cost of 1 bag of chips )

equation: 2.5 + 3c = 5.05

solution: cost of 1 bag of chips = $ 0.85 and cost of 3 bags of chips = $ 2.55

Given that, student bought two juice pouches for $1.25 each and 3 bags of chips

Let "c" be the price of 1 bags of chips

cost of 1 juice pouches = $ 1.25

Total cost = $ 5.05

Therefore, we frame a equation as:

two juice pouches x cost of 1 juice pouches + 3 bags of chips x price of 1 bags of chips = 5.05

Solve the above equation for "c"

Thus cost of 1 bag of chips = $ 0.85

Thus, cost of 3 bags of chips = $ 0.85 x 3 = $ 2.55

step-by-step explanation: a reaction is first order. if the initial reactant concentration is 0.0200 m, and 25.0 days later the concentration is 6.25 x 10-4 m, then its half-life is: