Five cards are dealt from a standard 52-card deck. what is the probability that we draw (a) 3 aces and 2 kings? (b) a "full house" (3 cards of one kind, 2 cards of another kind)?

 a) 9.23×10⁻⁶ and b) 0.00144

Step-by-step explanation:

Since we have given that

Number of cards = 52

a) Probability that we draw 3 aces and 2 kings.

As we know that

Number of aces = 4

Number of kings = 4

Number of cards drawn = 5

So, the probability becomes,

(b) a "full house" (3 cards of one kind, 2 cards of another kind)

Since there are 13 sets of each type  and we have to select and 2 kinds of it, so, it becomes

So, it becomes,

Hence, a) 9.23×10⁻⁶ and b) 0.00144

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

the square root of what number? if you add that, then someone will probably answer the question.