Eights rooks are placed randomly on a chess board. what is the probability that none of the rooks can capture any of the other rooks? translation for those who are not familiar with chess: pick 8 unit squares at random from an 8 × 8 square grid. what is the probability that no two chosen squares share a row or a column? hint. you can think of placing the rooks both with or without order, both ap- proaches work.

Step-by-step explanation:

There are only 2 solutions for none of the rooks can capture any of the other rooks: only if they are laid out in either of the 2 diagonal of the chess board

The number of possible combination for the rock to laid out in 8x8 (64 slots) chess board

possible combination

So the probability is pretty thin

answer: what if i dont want to show my work boi.

step-by-step explanation: im watching dbz and eating popcorn leave meh alone

mxb67

step-by-step explanation: