The prism shown is 35 .

work out h, the height of the triangular cross section.

i need with this

The height of the prism is h=2.5 cm.

Given information:

The volume of the prism is .

The base of the prism is a rectangle with sides 4 cm and 7 cm. 4 cm side is the base of the triangular face.

So, the volume of the prim can be written as,

The value of h can be calculated as,

Therefore, the height of the prism is h=2.5 cm.

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Step-by-step explanation:

we know that

The volume of the triangular prism is equal to

where

B is the area of the triangular base

L is the length of the prism

we have

substitute

solve for B

Find the height of the triangle

The area of triangle is equal to

substitute the given values

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

x = 12

y = 1

for the points!