Consider a triangle formed by connecting the three points: (0 0 0), (1 0 0), (1 1 1). a. find the vector which is perpendicular to the surface of this triangle, and has a positive z-direction?

=k−j   or (0 -1 1)

Step-by-step explanation:

The Vector or Outer Product two vectors, say →x&→y, is  

denoted by →x×→y, is a perpendicular vector to the plane containing them.

The given pts. A (0 0 0), B (1 0 0), C (1 1 1) lie in a

plane ABC.

As suchType equation here., the vectors (→(AB ) )and (→AC ) are members, ∈ of the plane ABC

That is □(→(AB )×(→AC))  to the plane ABC

(→(AB ) )=(1-0,0-0,0-0)=(1,0,0)

(→(AC ) )=(1-0,1-0,1-0)=(1,1,1)

(→(AB )×(→AC=  (0i -j  k)

=k−j  

Which is in the positive Z direction

your answer is a

step-by-step explanation:

4*4*4*4=256

i need a picture

step-by-step explanation: