If the length of side ac is 6 units, the length of side bc is 11 units, and the length of side xz is 36 units, what is the length of side yz?

66 units

Step-by-step explanation: I’m assuming that triangles XYZ and ABC are similar and side AC is similar to side XZ and side BC is similar to side YZ. The ratio of side XZ to side AC is 6. Therefore, you should multiply side BC by 6 to get side YZ. 11*6=66

your answer is b ^w^ hope i

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3