In a class of 777, there are 444 students who play soccer. if the teacher chooses 333 students, what is the probability that none of the three of them play soccer?

Step-by-step explanation:

Given:

Total number of students in a class = 7

Number of students who play soccer = 4

Number of students who don't play soccer = 3

Now, number of ways of choosing 3 students out of 7 students is given by their combination.

So, number of ways of choosing 3 students (S)=

Now, number of choosing 3 students who don't play soccer out of 3 students is given by their combination and is given as:

N =  

Therefore, the probability that none of the three of them play soccer is given as:

Therefore, the the probability that none of the three of them play soccer is

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right