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the equation y-5-6(x+1) is written in point-slope form. what is the equation written in slope-intercept form?

y = 6x + 11

Step-by-step explanation:

The slope-intercept form ⇒ y = mx + c

Where m is the slope and c is y-intercept

So, we need to change point-slope form to slope-intercept form

The given equation:  y - 5 = 6 (x+1)

∴ y - 5 = 6x + 6     add 5 to each side of the equation

∴ y = 6x + 6 + 5

∴ y = 6x + 11

So, the equation written in slope-intercept form is y = 6x + 11

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation: