Use technology or a z-score table to answer the question.
the scores for a golf tournament are normally distributed with a mean of 210 and a standard
deviation of 80. ella scored 230 at the tournament
what percent of golfers scored less than ella?
round your answer to the nearest whole number

a: 60%
b: 75%
c: 77%
d: 80%

A:60%

Step-by-step explanation:

Since the scores for a golf tournament are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = scores for the tournament.

µ = mean score

σ = standard deviation

From the information given,

µ = 210

σ = 80

We want to find the probability percent of golfers that scored less than Ella. It is expressed as

P(x < 230)

z = (230 - 210)/80 = 0.25

Looking at the normal distribution table, the probability corresponding to the z score is 0.5987

Therefore, the percent of golfers that scored less than Ella is

0.5987 × 100 = 59.87

Approximately 60%

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1