Adeadly virus runs through the beetles in big city. if there are 1280 beetles in the city and every week 20% of them die, how many beetles remain after 6 weeks?

336 beetles remain after 6 weeks.

Step-by-step explanation:

If there are 1280 beetles in the city and every week 20% of them die, then the rate is exponential. The formula for determining the number of beetles left in the city after t weeks would be

A = P(1 - r/n)^nt

Where

A represents the number of beetles left after t years.

P represents the initial number of beetles

r represents the death rate of the beetles.

n represents the periodic record of the death.

t represents the number of weeks.

From the information given,

P = 1280

r = 20/100 = 0.2

n = 1(recorded weekly)

t = 6 weeks

Therefore,

A = 1280(1 - 0.2/1)^1 × 6

A = 1280(0.8)^6

A = 336

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

3/6 chance

step-by-step explanation:

half of the nubers are odd numbers (1,3,5) which in that case if you would be told to simplify it would be 1/2