If sin a= 12/13 in quad. 2 , cos b=-4/5 quad 3, how do i find sin (a+b) ?

Therefore

Step-by-step explanation:

Given:

To Find:

Solution:

Using identity,

Now Substitute Sin a we get

As 'a' is in Second Quadrant Cos a is Negative

Similarly,

Now Substitute Cos b we get

As 'b' is in Third Quadrant Sin b is Negative

Now Using Identity

Substituting the values we get

Therefore

associative property hopes this ! : )

step-by-step explanation:

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

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