Find an equation of the line that passes through the points. (let x be the independent variable and y be the dependent variable.)
(−3, −6) and (5, −8)

Step-by-step explanation:

The equation of a line is:

y = mx + b

Where:

m = slope

b = y-intercept

First thing we need to do is solve for the slope. The slope formula is:

Where:

x₁ = x-coordinate of the first point

x₂ = x-coordinate of the second point

y₁ = y-coordinate of the first point

y₂ = y-coordinate of the second point

We are given the following points:

Point 1: (-3, -6)

Point 2: (5, -8)

So let's plug in our coordinates into the slope formula:

So we have our new equation of this line:

What do we do then about the y-intercept?

Our points will help us out by plugging them in our equation, so we can solve for our y-intercept (b).

Let's do both to show that it would be the same:

Point 1 (-3, -6)

Point 2: (5, -8)

Now that we have b, we can insert that into the equation of the line:

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

answer: i think it's a

step-by-step explanation: