Identify the equation of the circle that has its center at (10, 24) and passes through the origin.
a. (x−10)2+(y−24)2=676
b. (x−10)2+(y−24)2=576
c. (x+10)2+(y+24)2=676
d. (x+10)2+(y+24)2=576

A )  The Equation of the circle (x−10)2+(y−24)2=676

Step-by-step explanation:

step1:-

The equation of the circle whose center is (a,b) and radius r is

in this circle equation centre is (g,f) = (10,24)

and formula of radius of a circle is

r =

Step2:-

The Equation of the circle (x−10)^2+(y−24)^2=676

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204