The line with equation x + y = 0 coincides with the terminal side of an angle θ in standard position in quadrant ii .

what is the value of tanθ ?

tanθ = -1

m=tanθ = -1

Step-by-step explanation:

Step 1:-

using formula m=tanθ

Given straight line is x+y=0

The given straight line is passing through the origin so y = -x

straight line is passing through the origin so y = m x

m = -1

Step3:-

The line with equation x+y=0 with the terminal side of an angle θ in standard position in Quadrant II i.e., θ = 90+45=135

 m  = tanθ

 m  = tan(90+45)

  m   = - cot 45

   m   = -1

Step4:-  m =tanθ =-1

answer: add the !

step-by-step explanation: then we will answer

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation