Find the 1st , 2nd (median) and 3rd quartile of the set of numbers 6,8,2,6,7,9 ?

at first we put the numbers in order from least to greatest

2 , 6 , 6 , 7 , 8 , 9

1st quartile = 6

median = (6+7)/2 = 6.5

3rd quartile = 8

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.