Apopulation has a mean, μ = 89 and a standard deviation,σ = 24.
find the mean and standard deviation of a sampling distribution of sample means with sample size n = 64.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

Let X the random variable of interest for a population. We know from the problem that the distribution for the random variable X is given by:

We take a sample of n=64 . That represent the sample size.

The sample mean is defined as:

And if we find the expected value and variance for the sample mean we got:

Var(\bar X) = \frac{\sigma^2}{n}[/tex]

The distribution for the sample mean is given by:

answer: 457.14

step-by-step explanation:

205 - 45 = 160

160 / .35 = 457.142857

3201

step-by-step explanation: