Jess and wes used to race each other when they were younger. jess could cover 8
meters per second, but wes could cover only 5 meters per second, so jess would sportingly
let wes start 60 meters ahead. they would both start at the same time and continue
running until jess caught up with wes. how far did jess run in those races?

160 meters

Step-by-step explanation:

Let call dj  distance run by  Jess    and   dw  distance run by Wes

By Jess courtesy Wes will be  60 meters ahead of Jess

Let call t the time in which both runners are at the same point, which in fact is when both distances are equal

dj  =  8 m/sec * t        and    dw  =  60  +  5 m/sec * t

Then we make  dj = dw

8*t  =  60 + 5*t

3*t  =  60

t = 20 sec

Now passed 20 sec  dj   =   8 * 20   = 160 m

and   dw = 60 + 5*20   dw  =  160 m

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic