Aman deposits 45 into an account the next day he makes 3 deposits of 20 $ each a week later he withdraws 105$

The amount available in account at last is $0  

Step-by-step explanation:

Given as :

The withdrawal amount from the account at the end = $105

The first deposit amount = $45

The next three deposit amount = $20 each

I.e The second deposit amount = 3 × $20

Or, The second deposit amount = $60

Let The amount available in account at last = $A

Now, According to question

The amount available in account at last = (first deposit amount  + second deposit amount) - withdrawal amount from the account at the end

i.e A = ($45 + $60) - $105

Or, A = $105 - $105

∴  A = $0

So, The amount available in account at last = A = $0

Hence, The amount available in account at last is $0   . Answer

687.09 dollars       happy now

step-by-step explanation: 6870

1857 times .63 equals 1169.91 subtract that from 1857 you get 687.09

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24