Identify the equation in slope-intercept form for the line containing the point (2,1) and parallel to y=53x−13.

Y=53X-105

Step-by-step explanation:

So it's a parallel, keep the y=53x

Then, make an equation

(_)=(53)(_)+b

Place the coordinates you have inthe blanks the 1 goes where y goes

The 2 goes where X goes

(1)=(53)(2)+b

Multiply 53 and 2 for 106

Subtract 106 from 1.

-105 is your intercept.

Add it all together

Y=53X-105

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4th option is correct xy=-10

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