There are 60 students in a class among which 30 are boys. in another class there are 50 students among which 25 of them are boys. if one from each class is selected, [2]
(a) what is the probability of both being girls ?
(b) what is the probability of having at least one girl?
explain also

A).= 1/2 probability of selecting girls.

B).= 1/2

Step-by-step explanation:

because there are 30 boys out of sixty which makes it half the class.

then theres 25 boys out of 50. therefore the answer is 1/2

a) Probability of both being girl = 1/4

b) Probability of having atleast one girl = 1

Step-by-step explanation:

Let name the two classes: Class A and Class B respectively.

Class A = 60 students, 30boys and 30girls

Class B = 50 students, 25boys and 25girls

a) Probability of both being girls=

Probability of selecting girl in Class A * Probability of selecting girl in Class B

Probability of both being girls = 30/60 * 25/50

= 1/2 x 1/2

= 1/4

Probability of both being girls = 1/4

b) probability of having atleast one girl = Probability of selecting girl in Class A + Probability of selecting girl in Class B

Probability of both being girls = 30/60 + 25/50

= 1/2 + 1/2

= 1

Probability of having atleast one girl = 1

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation: