What is the slope of the line that passes through the pair of points (-10,14) and (-6,12).

Step-by-step explanation:

(-10,14) and (-6,12)

y2 = 12, y1 = 14, x2 = -6, x1 = -10

Slope m = (y2 - y1)/(x2 - x1)

m = (12 - 14)/(-6 + 10)

m = -2/4

m = -1/2

The equation of line

y - y1 = m(x - x1)

y - 14 = -1/2(x + 10)

y - 14 = -x/2 - 5

y = -x/2 - 5 + 14

y = -x/2 + 9

answer: 7270

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752