With no stops, it takes 3 hours for a motorist to make a trip driving at an average speed of 65 mph. when the motorist stops for gas and a sandwich on the same trip, he averages 60 mph. how many minutes long is the stop?

The  time for which motorist stop for gas and sandwich is 15 minutes

Step-by-step explanation:

Given as :

Let The distance cover by motorist = d miles

Let The time for which motorist stop = n minutes

The time taken by motorist to cover d distance with no stop = t = 3 hours

The average speed of motorist with no stop = s = 65 miles per hour

Again

The time taken by motorist to cover d distance with stop = T hours

The average speed of motorist with stop = S = 60 miles per hour

∵ Distance = Speed × Time

So, with no stop

d = s × t

Or, d = 65 miles per hour × 3 hours

Or, d = 195 miles

And, with stop

d = S × T

Or, d = 60 miles per hour × T hours

∵ d = 195 miles

So, 60 miles per hour × T hours = 195 miles

Or , 60 T = 195

∴ T =

i.e T = 3.25 hours

Or, T = 3 hours + hours

Or, T = 3 hours +   hours

Or, T = 3 hours +   minutes

Or, T = 3 hours + 15 minutes

So, time taken by motorist to cover d distance with stop = T = 3 h + 15 min

Now,

The time for which motorist stop = time taken by motorist to cover d distance with stop - time taken by motorist to cover d distance with no stop

i.e n = T - t

Or, n = ( 3 hours + 15 minutes) - ( 3 hours)

∴ n = 15 minutes

So, The time for which motorist stop = n = 15 minutes

Hence, The  time for which motorist stop for gas and sandwich is 15 minutes . Answer

1

step-by-step explanation:

it's the only multiple of both and the least

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2