If two distinct positive divisors of 64 are randomly selected, what is the probability that their sum will be less than 32?

The required probability is

Step-by-step explanation:

Since we have given that

Divisors of 64= 1,2,4,8,16,32,64

Sum would be less than 32

Since it has 7 divisors in total.

If we select any two distinct divisors from first five divisors, the sum will always less than 32.

So, the probability that their sum will be less than 32 is given by

Hence, the required probability is

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation:

6: 07 is your answer

step-by-step explanation: