Could somebody me? i'm struggling with this question: (

Slope is the charge per hour, y-intercept is the flat fee earned by Nicole and the equation to find the cost per hour is  

For hours of babysitting amount earned is .

Step-by-step explanation:

From the given data lets assign time on x-axis and the amount earned on y-axis.

We have to choose two points.

and

By applying point slope form we have to find the slope of the points.

Slope (m)

Here slope is representing per hour charge of Nicole for babysitting.

Now lets find the y-intercept value by plugging the values of in standard equation of line that is ,equivalent to where is the y-intercept.

The equation for cost (C), , is the number of hours.

This y-intercept is representing the flat fee Nicole will charge for babysitting.

Now

For hours cost we will put in the equation of cost.

For hours of baby sitting Nicole will earn an amount of

So our final answers are equation of cost , y-intercept is the flat fee and slope is the charge per hour.For hours amount earned is .

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}