Try to get all !

subtract.

question 1--7 3/4 - 3 1/8

a.) 4 1/4
b.) 4 7/8 '
c.) 4 2/4
d.) 4 5/8

question 2-- subtract

6 1/9 - 4 1/9

a.) 2 7/9
b.) 2 5/9
c.) 2 4/9
d.) 2 2/9

question 3-- susie bought 4 3/4 pounds of cherries at the store. she ate 5/8 of a pound on the way home. how many pounds of cherries does she have left? enter your answer in the box as a mixed number in simplest form.

type answer..

question 4-- bob had 6 1/2 qt of paint. he used 3 2/3 qt to paint a room. how much paint does bob have left? enter you answer in the box as a mixed number in simplest form.

type answer. \

question 5 (last marcus needs 3 1/10 m of blue fabric and 1 1/5 m of yellow fabric to make his costume. how much more blue fabric than yellow fabric does marcus need? express your answer as a mixed number in simplest form.

get all correct

the answer is d on edge

step-by-step explanation:

what

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.