Average height of men is normally distributed with a mean of 62 inches and a standard deviation of 2 inches. determine the z-score for a man with a height of 67 inches.

the z-score for a man with a height of 67 inches is 2.5

Step-by-step explanation:

Since the average height of men is normally distributed, we would apply the formula for normal distribution. It s expressed as

z = (x - u)/s

Where

x = height of men

u = mean height

s = standard deviation

From the information given,

u = 62 inches

s = 2 inches

We want to determine the z-score for a man with a height of 67 inches.

For x = 67,

z = (67 - 62)/2 = 2.5

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.