Which statement explains why abc is congruent to a a'b'c' ?

The two given triangles ABC and A'B'C' are congruent by SSS or AA axiom of congruence.

Step-by-step explanation:

Rigid Transformation is a transformation which PRESERVES (keeps it SAME) the LENGTH and the ANGLES in an image and pre- image.

Here, as we can ΔABC goes under Rigid Transformation in to the ΔA'B'C'

⇒Sides AB, BC and AC correspond to the sides A'B',B'C' and A'C' respectively.

Also the ∠A, ∠B and∠C correspond to  ∠A', ∠B' and∠C' respectively.

Now, in  ΔABC and ΔA'B'C

AB  = A'B'

BC  =   B' C'

AC  = A'C'

⇒The two given triangles are congruent by SIDE SIDE SIDE property.

Also, ∠A  = ∠A'

∠B  =   ∠B'

⇒The two given triangles are congruent by ANGLE ANGLE property.

Hence the two given triangles ABC and A'B'C' are congruent by SSS or AA axiom of congruence.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

what is the graph

step-by-step explanation: