Mathematics, 15.01.2020 06:31 123martinnnnn

Resource allocation: each day an organism has 100 j of energy to divide between growth and reproduction. each millimeter of growth costs 3 j and each egg produced costs 5 j. denote the amount of growth per day by x1 and the number of eggs produced per day by x2. (a) suppose that the organism divides its energy so that for every millimeter of growth that occurs each day, it produces (on average) two eggs. what is the amount of growth and number of eggs produced on each day? (b) suppose that the organism divides its energy each day so that the total energy spent on eggs is twice that spent on growth. what is the amount of growth and number of eggs produced on each day?

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Answer from: cindy14772

a. 7.69 mm and 15 eggs

Step-by-step explanation:

a. First, we have to write down the equivalent equations given by the statement. Therefore, the equations can be written as follows:

E1: 3x_1+5x_2=100

E2: $x_2=2x_1\\2x_1-x_2=0$

If we replace E2 inside E1 we can get:

$3x_1+5(2x_1)}=100\\3x_1+10x_1=100\\13x_1=100\\x_1=7.69 mm$

Now replacing this result in E2 we get:

$x_2=2\times 7.69 = 15.4$

The organism produces 15 eggs on average and growths 7.69 mm per day.

b. Now, we need to define E2 in terms of energy as follows:

E3: $5x_2=2 \times 3x_1\\x_2= \frac{6}{5}x_1$

If we replace E3 in E1 we get:

$3x_1+5(\frac{6}{5}x_1)=100\\9x_1=100\\x_1=\frac{100}{9}=11.11 mm$

Now replacing this result in E3 we get:

$x_2=\frac{6}{5}\frac{100}{9}=\frac{40}{3}= 13.33$

The organism produces 13 eggs on average and growths 11.11 mm per day.

Answer from: Quest

x = 23.78

step-by-step explanation:

Answer from: Quest

x= 1

step-by-step explanation: convert 5\frac{11}{12}5

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{5\times 12+11}{12}3.25+0.5x+1

5×12+11

2 simplify 5\times 125×12 to 6060

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{60+11}{12}3.25+0.5x+1

60+11

3 simplify 60+1160+11 to 7171

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{71}{12}3.25+0.5x+1

4 simplify \frac{5}{6}x

x to \frac{5x}{6}

3.25+0.5x+1\frac{1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+1

5 convert 1\frac{1}{3}1

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+\frac{1\times 3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

1×3+1

6 simplify 1\times 31×3 to 33

3.25+0.5x+\frac{3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3+1

7 simplify 3+13+1 to 44

3.25+0.5x+\frac{4}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

8 simplify 3.25+0.5x+\frac{4}{3}+\frac{5x}{6}3.25+0.5x+

to \frac{13.75}{3}+\frac{4x}{3}

13.75

\frac{13.75}{3}+\frac{4x}{3}=\frac{71}{12}

13.75

9 simplify \frac{13.75}{3}

13.75

to 4.5833334.583333

4.583333+\frac{4x}{3}=\frac{71}{12}4.583333+

10 subtract 4.5833334.583333 from both sides

\frac{4x}{3}=\frac{71}{12}-4.583333

−4.583333

11 simplify \frac{71}{12}-4.583333

−4.583333 to \frac{4}{3}

\frac{4x}{3}=\frac{4}{3}

12 multiply both sides by 33

4x=\frac{4}{3}\times 34x=

×3

13 simplify \frac{4}{3}\times 3

×3 to \frac{12}{3}

4x=\frac{12}{3}4x=

14 simplify \frac{12}{3}

to 44

4x=44x=4

15 divide both sides by 44

x=1

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Resource allocation: each day an organism has 100 j of energy to divide between growth and reproduc...