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Mathematics, 15.01.2020 04:31 anthonyherd18

2\dfrac{1}{4} \div \left(-3\dfrac{1}{3}\right) =βˆ’2
4
1

Γ·(βˆ’3
3
1

)=minus, 2, start fraction, 1, divided by, 4, end fraction, divided by, left parenthesis, minus, 3, start fraction, 1, divided by, 3, end fraction, right parenthesis, equals

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2\dfrac{1}{4} \div \left(-3\dfrac{1}{3}\right) =βˆ’2
4
1

Γ·(βˆ’3
3
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