Using a property of logarithms demonstrate that
in x/in y≠ inx/y = in x - in y
by using a spreadsheet to complete the table.
x y inx/iny inx/y in x - in y
1 2
3 4
10 5
4 0.5

Dividing logarithms is not the same as dividing the arguments of a logarithm.

Step-by-step explanation:

1) If we divide two logarithms then we'll find a value. This is not the same as dividing two arguments of the same base logarithms.

For example:

Then

2) Completing the table below to show it clearly:

hence, the required result is

step-by-step explanation:

suppose we have two matrices a and b

we will assume the two matrices

we have to compute b-a which means subtracting corresponding elements of a from b.

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