Find an equation of a sphere with center (2,-3,6) that touch (a) the xy-plane, (b) the yz-plane, (c) the xz-plane.

Step-by-step explanation:

To find the equation of a sphere with center (2,-3,6) that touch

(a) the xy-plane,

The equation of xy plane is z=0

Hence the radius would be distance from z=0 perpendicular to xy plane = z coordinate =6

Equation is

(b) the yz-plane,

The equation of yz plane is x=0

Hence the radius would be distance from x=0 perpendicular to yz plane = x coordinate =2

Equation is

(c) the xz-plane.

The equation of zx plane is y=0

Hence the radius would be distance from y=0 perpendicular to zx plane = |y coordinate| =3

Equation is

answer: youre the sweetest thing for that

step-by-step explanation:

hihi so drawing these 2 triangles is fairly simple. all that's left is finding the height of each one. luckily, we have a side length and an angle, so there is a trig function we can use to solve for the height. the easiest one to use would be tangent, since we have 2/3 things needed to find and the third needed is what we are solving for. tan(73°) * 30 ~= 98.13 and tan(73°) * 35 ~= 114.45