Demand the demand function for a product is modeled by
p = 8000(1 - 5/5 + e-0.002x).
find the price p (in dollars) of the product when the quantity demanded is (a) x = 1000 units and (b) x = 2500 units, (c) what is the limit of price as x increases without bound?

a) 210.8 b) 10.77 c) 0

Step-by-step explanation:

a)p = 8000(1 - 5/5 + e^-0.002x).

when x = 1000 units

p = 8000 (  1 - (5 / (5 + e ^(-0.002 × 1000)))= 210.8

b) when x = 2500

p = 8000 (  1 - (5/(5 + e ^(-0.002 × 2500)))

p = 10.77

c) [/tex]

p = 8000 (  1 - (5/(5+ e^(-0.002∞)))

p = 8000 (  1 - (5 / (5+ e^-∞))

e^-∞ = 0

p =8000( 1- (5/5))

p = 8000 (1-1) = 0

the limit of price as x increase without bound reduces to zero

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

my answer got deleted but it's a

step-by-step explanation: