In exercise, use the properties of logarithms to rewrite the expression as the logarithm of a single quantity.
in x + 4 in y - 1/2 in (z + 4)

ln[xy/sqrt(z+4)]

Step-by-step explanation:

lnx+ln(y^4)-ln((z+4)^1/2)

The logarithms property states that logxy can be written as log(x)+log(y)

ln(xy)-ln(z+4)^1/2

The logarithms property also states that logx/y can be written as log(x)-log(y)

ln(xy)/ln(z+4)^1/2

ln(xy/(z+4))^1/2

ln[xy/sqrt(z+4)]

Hence by using the logarithms properties In x + 4 In y - 1/2 In (z + 4) can be written as ln[xy/sqrt(z+4)]

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: