Solve the system of equations. 3x+4y=−23 x=3y+1

Step-by-step explanation:

3x+4y=−23(1)

x=3y+1 (2)

Putting (2) in (1)

3(3y + 1) + 4y = -23

9y + 3 + 4y = -23

9y + 4y = -23 - 3

13y = -26

y = -26/13

y = -2

Putting y into (2)

x=3y+1

x = 3(-2) + 1

x = -6 + 1

x = -5

The solution to the equation is (-5, -2)

Given the system of equations

Substitute eqn 2 into 1 to have:

3x+4y=−23

3(3y+1)+4y=−23

9y + 3 +4y = -23

13y = -26

y = -2

Since x = 3y + 1

x = 3(-2) + 1

x = -5

Hence the solution to the equation is (-5, -2)

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x = 12

y = 15

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