Find the angle measuments of a triagle in which one angle measures 10 degress less than twice the second triangle, and the third angle measures 25 degrees more than the second angle.

the first angle is 72.5 degrees.

The second angle is 41.25 degrees.

The third angle is 66.25 degrees

Step-by-step explanation:

Let x represent the size of the first angle.

Let y represent the size of the second angle.

Let y represent the size of the second angle.

one angle measures 10 degress less than twice the second triangle. This means that

x = 2y - 10

the third angle measures 25 degrees more than the second angle. This means that

z = y + 25

The sum of the angles in a triangle is 180 degrees. This means that

x + y + z = 180 - - - - - - - - - - 1

Substituting x = 2y - 10 and z = y + 25 into 1, it becomes

2y - 10 + y + y + 25 = 180

4y + 15 = 180

4y = 180 - 15 = 165

y = 165/4 = 41.25 degrees

x = 2y - 10 = 41.25 × 2 - 10 = 72.5 degrees

z = x + 25 = 41.25 + 25 = 66.25 degrees

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18