Every 12 hours, pete's standard clock advances 19 hours. if pete's clock is correct at 6: 00 am on the morning of june 1st, what time will his clock read at 6: 00 am on the morning of july 1st?

12 PM

Step-by-step explanation:

Given:

Pete's clock advances by 19 hours for for every 12 hrs.

As, 1 Day = 24 hrs

Number of slots of 12 hrs in 1 day = 2

Number of slots of 12 hours in June month = 2*Number of days in June

Number of slots of 12 hours in June month = 2*30 = 60

Hence, from 1st June to 1st July , no of advancing hours given by :

Total advance hours = 60*19 = 1140

1140 /24 = 47.5

47 gives full days 0.5 gives 6 hours extra.

So, it will read 6 hours more than actual time.

Clock reads : 12 pm

6:00pm

Therefore the time on Pete's clock would be

6:00am + 12 hours

= 6:00pm

Step-by-step explanation:

Given that the clock advances 19 hours in 12 hours .

Number of days between june 1st and july 1st = 30 days.

Number of 12 hours between June 1st and July 1st = 30 × 2 = 60

(there are 24 hours in a day, so there is 2 × 12 hours in a day)

For the normal clock, in 30 days it would have moved

60 × 12 hours = 720 hours

For pete's clock , in 30 days it would have moved

60 × 19 = 1140 hours

The amount of extra hours Pete's clock would have moved is

1140-720 = 420 hours

Number of Extra 24 hours moved is

420/24 = 17.5

So Pete's clock have moved;

17(24) + 0.5(24)

17 days + 12 hours

Therefore the time on Pete's clock would be

6:00am + 12 hours

= 6:00pm

(Though in case of an analogue clock 6:00 am and 6:00pm may be seen as the same)

i dont know sorry

step-by-step explanation: