A(n) = -1/16[tex](2)^{n-1}[/tex]
what is the 4th term in this geometric sequence?...
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Mathematics, 12.01.2020 23:31 hannahv10
A(n) = -1/16![(2)^{n-1}](/tex.php?f=(2)^{n-1})
what is the 4th term in this geometric sequence?
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