Solve the equation.
x2 − x − 12 = 0
a) x = 4
b) x = −3
c) x = −3 or x = 4
d) x = −4 or x = 3

C

Step-by-step explanation:

In this technique, if we have to factorise an expression like ax2+bx+c, we need to think of 2 numbers such that:

N1⋅N2=a⋅c=1⋅−12=−12

AND

N1+N2=b=−1

After trying out a few numbers we get N1=3 and N2=−4

3⋅−4=−12, and 3+(−4)=−1

x2−x−12=x2−4x+3x−12

x(x−4)+3(x−4)=0

(x+3)(x−4)=0

Now we equate the factors to zero.

x+3=0,x=−3

x−4=0,x=4

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

v,jhvljh,b.b; hk; ljujb,vuvccklokll; k,m,km,

step-by-step explanation: