How much candy at $1.20 a pound should be mixed with candy worth 95¢ a pound in order to obtain a mixture of 50 pounds of candy worth a dollar a pound?

10 pounds of candy costing $1.20 per pounds must be mixed with 40 pounds of candy costing $ 0.95 per pound to obtain a 50 pounds of candy costing $ 1 per pound

Solution:

Let "x" be the pounds of candy at $ 1.20 per pound

Then (50 - x) is the pounds of candy at $ 0.95 per pound ( since 95 cents is equal to 0.95 pound)

Therefore, x pounds of candy costing $1.20 per pounds must be mixed with (50 - x)  pounds of candy costing $ 0.95 per pound to obtain a 50 pounds of candy costing $ 1 per pound

Then the equation becomes,

1.20x + (50 - x)0.95 = 50 x 1

On expanding we get,

1.20x + 47.5 - 0.95x = 50

0.25x = 50 - 47.5

0.25x = 2.5

x = 10

Then (50 - x) = 50 - 10 = 40

So we need 10 pounds of candy worth $ 1.20 per pound and 40 pounds of candy worth $ 0.95 to obtain 50 pounds of candy worth a dollar a pound

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

idk wbu

step-by-step explanation: