Suppose that there are two types of tickets to show advance and same day the combine cost of one advanced ticket and one same day ticket to $70 for one performance 30 advance tickets and 25 same day tickets were sold the total amount paid for the tickets was $1950. what was the price of each kind of ticket

Step-by-step explanation:

x = advance and y = same day

x + y = 70x = 70 - y

30x + 25y = 1950

30(70 - y) + 25y = 1950

2100 - 30y + 25y = 1950

-5y = 1950 - 2100

-5y = - 150

y = -150/-5

y = 30 < there were 30 same day tickets

x + y = 70

x + 30 = 70

x = 70 - 30

x = 40 < there were 40 advance tickets

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w