Acandy maker offers child and adult bags of jelly beans with different color mixes. the company claims that the child mix has 30% red jelly beans, while the adult mix contains 15% red jelly beans. assume that the candy maker’s claim is true. suppose we take a random sample of 50 jelly beans from the child mix and a separate random sample of 100 jelly beans from the adult mix. let ^ p c and ^ p a be the sample proportions of red jelly beans from the child and adult mixes, respectively.

find the probability that the proportion of red jelly beans in the child sample is less than or equal to the proportion of red jelly beans in the adult sample, assuming that the company’s claim is true.

enter the probability here:

Using the normal distribution and the central limit theorem, it is found that there is a 0.0212 = 2.12% probability that the proportion of red jelly beans in the Child sample is less than or equal to the proportion of red jelly beans in the Adult sample.

In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:

For the Child mix, we have that:

For the Adult mix, we have that:

For the distribution of differences, we have that:

The probability that the proportion of red jelly beans in the Child sample is less than or equal to the proportion of red jelly beans in the Adult sample is the p-value of Z when X = 0, hence:

By the Central Limit Theorem:

has a p-value of 0.0212.

0.0212 = 2.12% probability that the proportion of red jelly beans in the Child sample is less than or equal to the proportion of red jelly beans in the Adult sample.

To learn more about the normal distribution and the central limit theorem, you can take a look at link

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