Which equation represents the line that contains the point (3, -4) and has a slope of 5/7?
y - 4 = 5/7(x + 3)
y - 3 = 5/7(x + 4)
y + 3 = 5/7(x - 4)
y + 4 = 5/7(x - 3)

D

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = and (a, b) = (3, - 4), thus

y - (- 4) = (x - 3), that is

y + 4 = (x - 3)

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15