Three consecutive odd integers have a sum of 45

13, 15, and 17

Step-by-step explanation: This problem states that the sum of 3 consecutive odd integers is 45 and it asks us to find the integers.

3 consecutive odd integers are represented as follows.

X ⇒ first integer

X + 2 ⇒ second integer

X + 4 ⇒ third integer

Since the sum of these is 45, our equation reads X + X + 2 + X + 4 = 45.

Simplifying on the left, we get 3x + 6 = 45. Subtract 6 from both sides of the equation to get 3x = 39 and divide both sides of the equation by 3 in order to get x by itself and x = 13

Since x, our first odd integer is 13, our next consecutive odd integer x + 2 would be 15 and x + 4 would be 17.

So 13, 15, and 17 are the 3 consecutive odd integers that add to 45.

the answer is 200

step-by-step explanation:

the way the question is worded, it seems to imply the $264 interest is simple interest, not compound interest.

the simple interest for 2 years is $264; the simple interest for 1 year is $132.

$132 interest on a $600 investment means an interest rate of (132/600)*100 = 22%.

the value of $200 at 22% interest compounded annually for three years is

200%281.22%29%5e3

the amount of interest is that value, minus the original $200.

ddd

step-by-step explanation: