There are 10 vehicles in a parking lot : 3 suvs and 7 trucks. what is the probability that any 7 randomly chosen parking spots have 2 suvs and 5 trucks or 3 suvs and 4 trucks

Number of Vehicles in parking lot = 10 [ 3 SUV + 7 Trucks]

Probability of an event =

Probability of choosing 7 Vehicles in a parking spot out of [10 vehicles=3 SUVs and 7 trucks] such that it has 2 SUVS and 5 trucks or 3 SUVS and 4 trucks =

Use this formula to find , C(n,r)=

C(3,2)=3, C(7,5)=21, C(7,4)=35,C(3,3)=1,C(10,7)=120

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d