Aresearch company desires to know the mean consumption of meat per week among people over age 40. a sample of 610 people over age 40 was drawn and the mean meat consumption was 3.1 pounds. assume that the population standard deviation is known to be 1.1 pounds. construct the 85% confidence interval for the mean consumption of meat among people over age 40. round your answers to one decimal place.

Step-by-step explanation:

Confidence interval for population mean is given by :-

 (1)

, where = Sample mean

= Critical z-value

= Population standard deviation.

n= Sample size.

As per given , we have

n= 610

Significance level for 85% confidence :

By z-table critical two tailed z-value :

Put all values in (1) , we get

Hence, the 85% confidence interval for the mean consumption of meat among people over age 40.  =

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step-by-step explanation:

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geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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